y^2/3-9y^1/3=-20

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Solution for y^2/3-9y^1/3=-20 equation: 


y in (-oo:+oo)

(y^2)/3-((9*y^1)/3) = -20 // + 20

(y^2)/3-((9*y^1)/3)+20 = 0

(y^2)/3-3*y+20 = 0

1/3*y^2-3*y+20 = 0

DELTA = (-3)^2-(1/3*4*20)

DELTA = -53/3

DELTA < 0

y belongs to the empty set

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